The two masses m1=2.3 kg and m2=5.5 kg are connected by a massless string passing through a massless pulley as shown in the Figure below. The system is released from rest when my is on the ground while m2 is at a height of h above the ground, then m2 hits the ground with a speed of 6.7 m/s.
Consider a one-dimensional crystal with two atoms in the basis. If the motion of the atoms is confined to one dimension, Newton's law yields the following equations of motion. is the mass of the heavy atoms, M2M2.
Consider two masses, and , connected by a light inextensible string. Suppose that the first mass slides over a smooth, frictionless, horizontal table, whilst the second is suspended over the edge of the table by means of a light frictionless pulley. See Fig. 30. Since the pulley is light, we can neglect its rotational inertia in our analysis.
May 22, 2012 · Two masses M1 = 4.00 kg and M2 = 7.10 kg are stacked on top of each other as shown in the figure. The static coefficient of friction between M1 and M2 is μs = 0.430. There is no friction between M2 and the surface below it. What is the maximum horizontal force that can be applied to M2 without M1 sliding relative to M2?
Using the values of mass 1 = 1.207 kg and mass 2 = 0.145 kg, I get an acceleration of 1.05 m/s 2. This is pretty close to the experimental value (seen above) at 1.109 m/s 2 . I'm happy.
Two bodies with masses m1 and m2 are both moving east with velocities of magnitudes v1 and v2, where v1 is less than v2. The magnitude of the velocity of the center of mass of this system of two bodies is 1) less than v1. 2) equal to v1. 3) equal to the average of v1 and v2. 4) greater than v1 and less than v2. 5) greater than v2.
two masses m1 and m2 are connected by an inextensible string and the system passes over a frictionless pulley . obtain a relationship between the acceleration of the system and tension in the srting.